Introduction & Context
The hydrocyclone is a centrifugal liquid‑solid separator widely employed in the starch industry to concentrate starch slurries. By introducing the feed tangentially, a high‑speed vortex generates a radial acceleration that forces denser starch particles toward the underflow, while the lighter water‑rich phase exits as overflow. Accurate prediction of the cut size, separation efficiency, and pressure drop is essential for sizing cyclones, arranging them in batteries, and ensuring energy‑efficient operation.
Methodology & Formulas
The calculation follows the physics embedded in the reference Python code, expressed with standard engineering symbols.
1. Unit conversions
\[
Q_{s}= \frac{Q_{h}}{3600}\qquad\text{(volumetric flow rate in m³·s⁻¹)}
\]
\[
\mu = \mu_{cP}\cdot10^{-3}\qquad\text{(dynamic viscosity in Pa·s)}
\]
\[
\Delta\rho = \rho_{starch}-\rho_{water}\qquad\text{(density difference, kg·m⁻³)}
\]
\[
\theta = \frac{\pi}{180}\, \theta_{deg}\qquad\text{(cone half‑angle in radians)}
\]
\[
\sin\theta = \sin\!\left(\theta\right)
\]
2. Hydraulic geometry
\[
A_{in}= \pi\left(\frac{d_{i}}{2}\right)^{2}\qquad\text{(inlet cross‑sectional area, m²)}
\]
\[
v_{in}= \frac{Q_{s}}{A_{in}}\qquad\text{(inlet velocity, m·s⁻¹)}
\]
3. Cut size (d₅₀)
\[
d_{50}= K_{d50}\,\sqrt{\frac{\mu\,D_{c}}{\Delta\rho\,v_{in}\,\sin\theta}}\qquad\text{(median cut size, m)}
\]
where \(K_{d50}\) is a dimensionless empirical factor (≈ 0.55 for standard geometries).
4. Separation efficiency
\[
\eta = 1-\exp\!\left[-\left(\frac{d_{p}}{d_{50}}\right)^{N_{exp}}\right]\qquad\text{(fractional efficiency)}
\]
with \(d_{p}\) the particle diameter of interest and \(N_{exp}\) the exponential shape parameter (≈ 1.5 for starch slurries).
5. Pressure drop
\[
\Delta P_{Pa}= \tfrac{1}{2}\,\rho_{slurry}\,v_{in}^{2}\,\bigl(1+K_{loss}\bigr)
\]
\[
\Delta P_{bar}= \frac{\Delta P_{Pa}}{10^{5}}\qquad\text{(pressure drop, bar)}
\]
\(K_{loss}\) is the overall loss coefficient (≈ 7.5) and \(\rho_{slurry}\) the bulk slurry density.
Empirical Validity Checks
| Parameter |
Condition |
Typical Range |
| Inlet‑to‑body diameter ratio |
\(0.15 \le \dfrac{d_{i}}{D_{c}} \le 0.25\) |
0.15 – 0.25 |
| Volumetric flow rate |
\(5 \le Q_{h} \le 20\) m³·h⁻¹ |
5 – 20 m³/h |
| Inlet velocity |
\(3 \le v_{in} \le 10\) m·s⁻¹ |
3 – 10 m/s |
| Density difference |
\(\Delta\rho > 50\) kg·m⁻³ |
> 50 kg/m³ |
| Pressure drop |
\(0.5 \le \Delta P_{bar} \le 8\) bar |
0.5 – 8 bar |
Worked Example: Hydrocyclone Sizing for Corn Starch Clarification
A process engineer needs to evaluate the performance of a single hydrocyclone unit for concentrating a corn starch slurry. The goal is to estimate the cut size, separation efficiency for the target starch particles, and the required operating pressure.
Known Parameters:
- Hydrocyclone diameter, \( D_{c} = 0.100 \ \text{m} \)
- Inlet diameter, \( D_{in} = 0.020 \ \text{m} \)
- Volumetric feed flow rate, \( Q_{h} = 10.000 \ \text{m}^{3}/\text{h} \)
- Target particle size, \( d_{p} = 20.000 \ \mu\text{m} \)
- Slurry dynamic viscosity, \( \mu_{cP} = 1.000 \ \text{cP} \)
- Slurry bulk density, \( \rho_{slurry} = 1020.000 \ \text{kg}/\text{m}^{3} \)
- Starch density, \( \rho_{starch} = 1500.000 \ \text{kg}/\text{m}^{3} \)
- Water density, \( \rho_{water} = 1000.000 \ \text{kg}/\text{m}^{3} \)
- Cone half-angle, \( \theta_{deg} = 20.000^{\circ} \)
- Empirical constant for cut size, \( K_{d50} = 0.550 \)
- Overall pressure loss coefficient, \( K_{loss} = 7.500 \)
- Exponential shape parameter, \( N_{exp} = 1.500 \)
Step-by-Step Calculation:
-
Perform unit conversions and compute derived hydraulic parameters.
The flow rate is converted to SI units: \( Q_{s} = \frac{10.000}{3600} = 0.0027778 \ \text{m}^{3}/\text{s} \).
The dynamic viscosity: \( \mu = 1.000 \times 10^{-3} = 0.001000 \ \text{Pa}\cdot\text{s} \).
The density difference is: \( \Delta\rho = \rho_{starch} - \rho_{water} = 500.000 \ \text{kg}/\text{m}^{3} \).
The cone half-angle in radians: \( \theta = \frac{\pi}{180} \times 20.000 = 0.349066 \ \text{rad} \).
The inlet cross-sectional area is: \( A_{in} = \pi \left( \frac{0.020}{2} \right)^{2} = \pi \times (0.010)^{2} = 0.00031416 \ \text{m}^{2} \).
The inlet velocity is therefore: \( v_{in} = \frac{Q_{s}}{A_{in}} = \frac{0.0027778}{0.00031416} = 8.842 \ \text{m}/\text{s} \).
The sine of the cone angle is: \( \sin\theta = \sin(20.000^{\circ}) = 0.3420 \).
-
Calculate the cut size \( d_{50} \).
Using the provided correlation:
\[
d_{50} = K_{d50} \cdot \sqrt{ \frac{\mu \cdot D_{c}}{\Delta\rho \cdot v_{in} \cdot \sin\theta} }
\]
\[
d_{50} = 0.550 \times \sqrt{ \frac{0.001000 \times 0.100}{500.000 \times 8.842 \times 0.3420} } = 0.550 \times \sqrt{6.614 \times 10^{-8}} = 0.550 \times 0.0002571 = 0.0001414 \ \text{m}
\]
The calculation yields a cut size of \( d_{50} = 141.4 \ \mu\text{m} \).
-
Estimate the separation efficiency for the target 20 μm particles.
Applying the exponential efficiency model with exponent \( N_{exp} = 1.5 \):
\[
\eta = 1 - \exp\!\left[-\left( \frac{d_{p}}{d_{50}} \right)^{N_{exp}} \right] = 1 - \exp\!\left[-\left( \frac{20.000}{141.4} \right)^{1.5} \right]
\]
\[
\left( \frac{20.000}{141.4} \right)^{1.5} = (0.1414)^{1.5} = 0.0532, \quad \eta = 1 - \exp(-0.0532) = 0.0518
\]
The result is a separation efficiency of \( \eta = 0.052 \) or \( 5.2\% \).
-
Compute the system pressure drop.
The pressure drop is calculated from the inlet dynamic head and loss coefficient:
\[
\Delta P_{Pa} = \frac{1}{2} \cdot \rho_{slurry} \cdot v_{in}^{2} \cdot (1 + K_{loss})
\]
\[
\Delta P_{Pa} = 0.5 \times 1020.000 \times (8.842)^{2} \times (1 + 7.500) = 510 \times 78.18 \times 8.5 = 338,900 \ \text{Pa}
\]
\[
\Delta P_{bar} = \frac{338,900}{10^{5}} = 3.389 \ \text{bar}
\]
This gives a pressure drop of \( \Delta P = 3.389 \ \text{bar} \).
-
Perform empirical validity checks.
The inlet diameter ratio \( D_{in}/D_{c} = 0.020/0.100 = 0.200 \) is within the typical range of 0.15–0.25.
The flow rate of \( 10.000 \ \text{m}^{3}/\text{h} \) is within the typical range for a 0.1 m hydrocyclone (5–20 m³/h).
The inlet velocity of \( 8.842 \ \text{m}/\text{s} \) is within the recommended range (3–10 m/s).
The density difference of \( 500.000 \ \text{kg}/\text{m}^{3} \) is sufficient for separation.
The calculated pressure drop of \( 3.389 \ \text{bar} \) is within an operable range.
Final Answer:
For the given hydrocyclone geometry and operating conditions:
- The calculated cut size (\( d_{50} \)) is 141.4 μm.
- The separation efficiency for 20 μm starch particles is 5.2%.
- The required system pressure drop is 3.39 bar.
The low efficiency for the target particle size indicates that a single unit of this design is not effective. A battery of hydrocyclones in series or a design with a smaller cut size would be required for effective starch concentration.