Reference ID: MET-2BFE | Process Engineering Reference Sheets Calculation Guide
Introduction & Context
Solid Distribution Uniformity (SDU) quantifies how evenly suspended particles—such as chocolate chips in cake batter—are dispersed throughout a stirred tank. In process engineering, SDU is a key performance indicator for mixing operations: poor uniformity leads to off-spec product, variable texture, or downstream separation issues. The metric is routinely used in food, pharmaceutical, and fine-chemical industries where batch integrity and regulatory compliance depend on consistent solids loading at every sampling location.
Pilot trials with these variables can yield 10–30 % improvement in residence-time uniformity.
Use the following rule set:
Empirical correlations suffice for similar vessel aspect ratios (<±20 %) and particle densities
Invoke CFD when internals, multiple feed points, or heat exchangers create 3-D effects that correlations ignore
CFD is justified for scale-ups beyond 5:1 volume ratio or when maldistribution costs exceed $1 M yr⁻¹ in lost yield
A hybrid approach—CFD to identify problem zones, then empirical tuning—often delivers the fastest ROI.
Worked Example – Checking Chocolate-Chip Uniformity in a Pilot-Scale Batter Mixer
A confectionery plant is scaling up a new muffin batter. To avoid “bottom-heavy” chocolate chips, the process engineer must verify that the Solid Distribution Uniformity (SDU) is ≥ 0.90 when the 30 cm pilot tank is run at 180 rpm. Samples are withdrawn at five elevations and three radial positions, and the chip mass fraction is measured.
Tank diameter: 0.3 m
Tank height: 0.3 m
Impeller diameter: 0.1 m
Impeller speed: 180 rpm (3.0 rps)
Batter density: 1100 kg m⁻³
Batter viscosity: 4.0 cP (0.004 Pa s)
Target chip mass fraction: 0.02 kg kg⁻¹
Measured chip mass fractions (15 samples): average 0.0199 kg kg⁻¹
Sum of squared deviations from target: 2.573 × 10⁻⁵
Calculate the Reynolds number to confirm turbulent regime:
\[
Re = \frac{\rho N D^2}{\mu}
= \frac{1100 \times 3.0 \times 0.1^2}{0.004}
= 8250
\]
\(Re = 8250\) indicates fully turbulent flow.
Compute the standard deviation of the measured mass fractions:
\[
\sigma = \sqrt{\frac{\sum (x_i - \mu_{\text{target}})^2}{n - 1}}
= \sqrt{\frac{2.573 \times 10^{-5}}{14}}
= 0.00136 \text{ kg kg}^{-1}
\]