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| Section summary |
|---|
| 1. Heat losses
through insulated pipe |
| 2. Example of heat
loss calculation of insulated pipe : Step by Step guide |
| 3. Free Excel calculation tool for
insulated pipe heat loss : pipe heat loss calculator Excel |
In factories, pipes are typically routed outside. This may not be a problem for most of products and circumstances, but in the case of winter conditions or if the product is sensitive to a loss of temperature adding an insulation layer to the pipe is helpful to limit the temperature loss and potential impact on production.

There is a heat transfer from the inside of the pipe to the outside air. The heat transfer is a combination of convection and conduction :
|
What if your pipe is NOT
insulated ?
Consult MyEngineeringTools.com webpage on Heat loss calculation for non insulated pipes |
The heat transferred from the inside of the pipe to the air can be calculated thanks to the following overall heat transfer equation : Q = U*A*(Ti-Ta)
The overall heat transfer coefficient can be calculated by summing the different resistances to heat transfer the following way :

With :
Q = heat loss (BTU/h)
Ao = heat transfer area (ft2)
U = overall heat transfer coefficient (BTU/h.ft2.F)
Ti = inside temperature (R)
Ta = air temperature (R)
r1 = inside radius of the pipe (ft)
r2 = outside radius of the pipe (ft)
r3 = outside radius of the pipe + insulation layer (ft)
λ1 = thermal conductivity of the pipe (BTU/h.ft.F)
λ2 = thermal conductivity of the insulation (BTU/h.ft.F)
hi = heat transfer coefficient on the inside of the tube
(BTU/h.ft2.F)
ho = heat transfer coefficient on the outside of the tube
(BTU/h.ft2.F)
The heat transfer coefficient has 2 components : one due to radiation heat exchange, and the other due to convection
In the shortcut calculation method presented in this page, the heat
transfer coefficient by radiation is assumed to be hr = 1
BTU/h.ft2.F, as the temperature at the surface of the insulating
material is expected to be low.
If wind is present, there is a tremendous influence on the heat transfer coefficient which can be estimated the following way : hc = 0.11*c*G0.6/D0.4
With :
hc = convection heat transfer coefficient (BTU/h.ft2.F)
c = specific heat (BTU/lb/F) = 0.24 for air
G = mass velocity of air (lb/h.ft2) = rho.v
rho = density (lb/ft3) = 0.075 for air
v = wind speed (ft/h)
Do = pipe diameter (ft)
The overall heat transfer coefficient can be calculated, then the heat loss through the insulation with : Q = U*A*(Ti-Ta)
With U calculated by substituting the heat transfer coefficient calculated above.
Considering a pipe a 66 mm external diameter and 10 m length that is transporting steam at 160c. What is the heat loss when the pipe is insulated by a 2 cm insulating material, while being located outside, in air at 20c and with wind at 10 km/h.
The pipe is in carbon steel, with a thermal conductivity of 142 W/m.K
The insulating material has a thermal conductivity of 0.086 W/m.K
It is assumed that the skin temperature of the pipe is equal to the temperature of the fluid, the resistance to heat transfer being on the outside of the pipe.
Di = 66 mm = 0.2165 ft
Do = 66mm+20*2 = 106 mm = 0.348 ft
L = 10 m = 32.8 ft
Ts = 160c = 320 F = 780 R
Ta = 20c = 68 F = 527.7 R
v = 10 km/h = 32808 ft/h
k1 = 142 W/m.K = 25 BTU/h.ft.F
k2 = 0.086 W/m.K = 0.05 BTU/h.ft.F
Considering G = mass velocity of air (lb/h.ft2) = rho.v
G = rho.v = 0.075*32808 = 2498.8 lb/h.ft2
The heat transfer coefficient can be calculated from the correlation given in paragraph 1.3 above :
h = 0.11*c*G0.6/Do0.4 = 0.11*0.24*2498.80.6 / 0.3480.4 = 4.4 BTU/h.ft2.F
The outside heat transfer coefficient is the sum of :
ho = hc+hr = 1 + 4.4 = 5.4 BTU/h.ft2.F
U = 1/(0.174/(0.0985*1500) + 0.174*ln(0.10825/0.0985)/25 + 0.174*ln(0.174/0.10825)/0.05 + 1/5.4) = 0.5 BTU/h.ft2.F
Q = U*Ao*(Ts-Ta) =4937.9 BTU/h
Source
[Chopey] Handbook of Chemical Engineering calculations, Chopey et al, McGraw Hill, 2004